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Area of a Rectangle and Square



Here we will observe how to establish the area of a rectangle and a square, and look at the area of a square formula and a rectangle making use of the diagonal length.



Area of a Rectangle or Square

The rectangle and the square are two of the most basic standard shapes in Geometry.

Establishing the area of a rectangle or a square turns out to be relatively straightforward when we know the length of the sides.


Square:

A square has a width and a height that are of the same length.

Standard square with width and height labelled.

Area  =  WIDTH × HEIGHT

=>   a × a   or   a2             This is the simplest area of a square formula.



Rectangle:

Now for a standard rectangle.

Rectangle with the width and height labelled appropriately.

Area  =  WIDTH × HEIGHT

=>  a × b

The differing values in the height and width in a rectangle result in the different labels.
But overall the area sum to perform is the same.



Examples    


(1.1) 
Square with sides of 6cm in length.

    Area  =  6cm × 6cm   =   36cm2




(1.2) 

What is the area of the following tennis court?

Layout of a tennis court from above,.

Solution   

Area  =  WIDTH × HEIGHT
23m × 8m  =  184m2



(1.3) 
If the area of a square is  25cm2.

What length are the sides of the square?

Solution   
b2  =  25cm2
b  =  √25  =  5

Each side of the square is  5cm in length.




(1.4) 

Rectangle with height length shown.

If the area of the rectangle above is  32cm2.

What length is the width of the rectangle?

Solution   

4 × w  =  32          ( ÷ 4 )

w  =  \bf{\frac{\tt{32}}{\tt{4}}}     =>     w  =  8

The width of the shown rectangle is  8m.






Area of a Square Formula,
Area of a Rectangle using Diagonal


There is also an alternative way to establish the area of a square, provided you know the value of the length of the diagonal.

How to find square area using the diagonal.,




Example    


(2.1) 

Square with a diagonal of 6cm.

Area  =  \frac{8^2}{2}   =   \frac{64}{2}   =   32

Area  =  32cm2




(2.2) 

When we know the width/length of a rectangle (l),  and the value of the diagonal (d).

There following formula can be used.

Area  =  l \sqrt{d^2 \space {\text{--}} \space l^2}



For the rectangle above.

Area  =  12 \times \sqrt{13^2 \space {\text{--}} \space 12^2}   =   12 \times \sqrt{25}   =   12 \times 5   =   60

Area  =  60cm2





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